Prob[G(n,p(n)) satisfies F} converges to zero.
Lynch asked the question and did the analysis, getting (for every F):
(i) Prob[G(n,p(n)) satisfies F] = cn^{-b}+ O(n^{-b-v}) for some v such
that b>v>0
or
(ii) Prob(G(n,p(n)) satisfies F) = O(n^{-v}) for every v>0.
Lynch conjectured that in case (ii) we have
(++) Prob(G(n,p(n)) satisfies F) = O(e^{-n^v)) for some v>0.
We prove it here.
Paper available at:
ftp://dimacs.rutgers.edu/pub/dimacs/TechnicalReports/TechReports/1995/95-52.ps.gz